B atom gets hybridised to sort 3 equivalent hybrid orbitals directed to a few comers of equilateral triangle with B atoms within the centre. Bond angle = 120°.
The chapters and subtopics stated beneath are according to the most current syllabus of Central Board of Secondary Education. The exhaustive information presented for every of those subtopics will information you through Anything you can be expecting to study in Class 12 Physics.
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Clarification: Resistance increases with increase in size and decreases with rise in cross-sectional space.
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Sometimes, like in noble gas, atoms would not have any attraction to achieve an electron. In that circumstance Vitality has to be provided.
Actinides. Group of 14 things during the seventh period immediately after actinium. Each Lanthanoids and actinoids are put in different panel at the bottom with the periodic table.
Response: The elements of Team I have only one electron within their respective valence shells and thus have a strong inclination to get rid CBSE Class 12 Mathematics of this electron. The tendency to lose electrons in turn, is dependent upon the ionization enthalpy. Since the ionization enthalpy decreases down the team hence, the reactivity of team 1 factors increases in precisely the same purchase Li < Na < K < Rb < Cs.
Answer: Mendeleev made use of atomic pounds as the basis of classification of features inside the periodic desk. He did stick with it and classify features into groups and intervals.
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Dilemma 10. Explain the diamagnetic conduct of P2 molecule on The premise of molecular orbital theory.
Question eight. Despite the fact that geometries of NH3 and H20 molecules are distorted tetrahedral, bond angle in h2o is lower than that of ammonia. Explore.
In predicting the nature from the molecules: Molecules with particular dipole moments are polar in nature and people of zero dipole times are non-polar in character.
Problem two. Aside from tetrahedral geometry, One more doable geometry for CH4 is sq. planar While using the four H atoms for the comers of the sq. and the C atoms at its centre. Explain why CH4 just isn't sq. planar?